a Right triangl wihe sid 3cm, 4cm and 5cm is rotated aboue the sides 3cm in length find the volume of the solid so obtained.
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it is rotated by 3cm therefore
h=3cm
r=4cm
it will form a cone.
volume of cone = piR^2h
=22/7×16×3
=150.8 cm^3.
h=3cm
r=4cm
it will form a cone.
volume of cone = piR^2h
=22/7×16×3
=150.8 cm^3.
deepak70:
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Since,The triangle is rotated about the side 3 cm.
Therefore, height is 3 cm.
Now, since 3,4,5 are Pythagorean triplet.
Therefore, 3cm and 4cm are measurements of two sides of right triangle perpendicular to each other and 5cm is length of the hypotenuse.
Hence 4cm is the radius of triangle.
So Volume of Cone is 1/3×22/7×4×4×3=352/7=50.28 cubic cm
Hence volume of Cone =50.28 cubic cm approximately.
Therefore, height is 3 cm.
Now, since 3,4,5 are Pythagorean triplet.
Therefore, 3cm and 4cm are measurements of two sides of right triangle perpendicular to each other and 5cm is length of the hypotenuse.
Hence 4cm is the radius of triangle.
So Volume of Cone is 1/3×22/7×4×4×3=352/7=50.28 cubic cm
Hence volume of Cone =50.28 cubic cm approximately.
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