a right triangle ABC, tan(A) = 3/4. Find sin(A) and cos(A).
In a right triangle ABC with angle A equal to 90°, find angle B and C so that sin(B) = cos(B).
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Step-by-step explanation:
In right angle triangle ABC
B is a right angle triangle
AB=4 , BC=3
AC=√4^2+3^2
AC=√16+9
AC=√25
AC=5
P=3, B=4 and H= 5
sinA=P/H= 3/5
CosA= B/H=4/5
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