a right triangle abc with sides 5cm 12cm 13cm 8s rotated about the side 12 cm find the volume of the air displaced by the triangle
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let hypotenuse =13cm
given triangle revolves around 12cm
radius=5cm
height=12cm
volume=1/3PI×r^2×H
volume=1/3×PI×5×5×12
vol.=100PIcm ^3 (nearly)
second case,
r=12cm
h=5cm
vol.=1/3×PI×12×12×5
vol.=240PI cm^3
the ratio is 100/240
5:12
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