A right triangle ABC with sides 5cm, 12cm and 13cm is revolved about the side 12cm find the volume of the solid so obtained
Answers
Answer
314.29 cm³ is the volume of the solid obtained.
Explanation
A right triangle ABC with sides 5cm, 12cm , and 13cm is revolved about the side 12cm.
Let us assume that ∠B = 90°
[Refer the Attachment for figure]
Here; AB = 12 cm, BC = 5 cm and AC = 13 cm
After resolving the triangle about side 12 cm, we get
Radius (r) = 5 cm
Height (h) = 12 cm
We have to find the volume of the solid obtained. For that we have to find the volume of the solid.
We know that
Volume of cone = πr²h
Substitute the known values in above formula
(approx.)
Question :--- A right triangle ABC with sides 5cm, 12cm and 13 cm is revolved about the side 12cm find the volume of the solid so obtained ?
Points Used :--
→ When a right ∆ is revolve around any sides to make a cone .
we have Three case :--
1) Revolve Around its Base :-
- Here, Radius of cone will become = Perpendicular Side of Right ∆.
- Height of cone = Base of Right ∆.
2) Revolve Around its Perpendicular Side :-
- Radius of cone = Base of Right ∆ .
- Height of cone = Perpendicular side of cone .
3) Revolve Around its Hypotenuse :--
- Here cone will be double .
- Height of cone = Hypotenuse of Right ∆.
- Radius of cone = ( Perpendicular * Base ) / Hypotenuse .
[ ओर हम इसको इस तरीके से आसानी से याद रख सकते है कि, जिस भी भुजा(side) से हम घुमाते है, वह भुजा हमारे cone की Height हो जाती है ll ]
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❁❁ Refer To Image First .. ❁❁
Solution :--
→ Right ∆ sides are given as 5, 12 and 13. and it revolves around side 12cm.
So, As told above , We can say that, (or we can see this in image . )
→ Height of cone = 12cm..
→ Radius of cone = 5cm.
Now, we have to Find volume of cone so formed.
☛ Volume of cone = 1/3 * π * (radius)² * Height
Putting values now , we get,
➠ Volume = 1/3 * π * (5)² * 12
➠ Volume = ( 25 * 3.14 * 4 )
➠ Volume = (100 * 3.14)
➠ Volume = (314)
➠ Volume = 314 cm³