a right triangle having sides 6 cm 8 cm and 10 cm is revolved about the side of length 8 cm find the volume of the solid so formed
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As the triangle is revolved at 8 cm it forms a cone of height 8 cm and radius 6cm.
Volume of cone = \frac{1}{3} π r² h
= \frac{1}{3} * \frac{22}{7} 6 * 6 * 8
= \frac{44}{7} * 48
= \frac{2112}{7}
=301.71 cm³:
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