Question

A right triangle of hypotenuse 13 cm and one of its side is 12 cm is made to revolve talking side 12 cm and its axis. Find volume and curved surface area of the solid so formed?
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Answer 1

Answer:

It forms a cone of side length = 13cm and height = 12cm and base radius = 5cm

Volume = pie* r^2 * (h/3) = (3.14*5*5*12)/3 = 314cubcm

curved surface area = Pie*L*r = 3.14*13*5 = 204sqcm

Answer 2

The solid formed is the 'cone' with a volume of 314 cm³ and a curved surface area of 204 cm².

Step-by-step explanation:

Given: Hypotenuse = 13 cm

One of the sides of cylinder = 12 cm

To Find: Volume and Curved Surface Area of the solid

Solution:

• Finding Volume and Curved Surface Area

Since the right triangle is revolved with one of its sides as an axis, the solid formed is a cone having $l = 13 \ cm$, $h = 12 \ cm$, and $r = 5 \ cm$.

Therefore, the volume of the cone is,

$V = \frac{1}{3} \pi r^2 h$

$\Rightarrow V = \frac{1}{3} \times 3.14 \times (5)^2 \times 12$

$\Rightarrow V = 314 \ cm^3$

And, the curved surface area is,

$CSA = \pi r l$

$\Rightarrow CSA = 3.14 \times 5 \times 13$

$\Rightarrow CSA = 204 \ cm^2$

Hence, the solid formed is the 'cone' with a volume of 314 cm³ and a curved surface area of 204 cm².