A right triangle whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed.
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surface area of cone(double)= 2(3.14 x 4(4+5) )
=226.08
volume of cone=2(1/3 x 22/7 x 4x4 x 3)
=2(50.2)
=100.4
divyanshikusum137:
First read the ques pls.
i think now its correct after editing
check it please i am begginer
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