A right triangle with sides 6, 8, and 10 cm is revolved about the side 8cm. find the volume and CSA of solid so formed.
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A right triangle revolved about side 8cm. So,
h=8cm
r=6cm
l=10cm
Volume of cone=(1/3)πr^2h
=(1/3)·(22/7)·6·6·8
By dividing and multiplying,
=(22/7)·2·6·8
=(2112/7)
=301.71 cm^3
=302 cm^3 [approximately]
CSA of cone=πrl
=(22/7)·6·10
By multiplying,
=(1320/7)
=188.57cm^2
=189cm^2 [approximately]
)
h=8cm
r=6cm
l=10cm
Volume of cone=(1/3)πr^2h
=(1/3)·(22/7)·6·6·8
By dividing and multiplying,
=(22/7)·2·6·8
=(2112/7)
=301.71 cm^3
=302 cm^3 [approximately]
CSA of cone=πrl
=(22/7)·6·10
By multiplying,
=(1320/7)
=188.57cm^2
=189cm^2 [approximately]
)
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