A right triangle with sides 6 cm, 8 cm and
10 cm is revolved about the side 8 cm.
Find the volume and the curved surface of
the solid so formed. NCERT Exemplar
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When a right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm, then solid formed is a cone whose height of a cone, h = 8 cm and radius of a cone, r = 6 cm. Slant height of a cone, l = 10 cm
Volume of a cone = 1/3 πr2h = (1/3) x (22/7) x 6 x 6 x 8
⇒ 6336/21 = 301.7 cm3
and curved surface of the area of cone = πrl
⇒ (22/7) x 6 x 10 = 1320/7 = 188.5 cm2
Hence, the volume and surface area of a cone are 301.7 cm3 and 188.5 cm2, respectively.
Volume of a cone = 1/3 πr2h = (1/3) x (22/7) x 6 x 6 x 8
⇒ 6336/21 = 301.7 cm3
and curved surface of the area of cone = πrl
⇒ (22/7) x 6 x 10 = 1320/7 = 188.5 cm2
Hence, the volume and surface area of a cone are 301.7 cm3 and 188.5 cm2, respectively.
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