a right triangle with sides 6cm 10cm 8cms is revolved about 8cm and 6cm find volume and curved surface area
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when it is revolved about 8 cm
radius = 6 cm, height = 8 cm. slant height, l = 10 cm
volume = (1/3)πr²h = (1/3)π×(6)²×8 = 96π cm³
curved surface area = πrl = π×6×10 = 60π cm²
and when it is revolved around 6 cm
radius = 8 cm, height = 6 cm, slant height , l =10 cm
∴ volume =(1/3)πr²h = (1/3)π×(8)²×6 = 192π cm³
slant height =πrl =π×8×10 = 80π cm²
radius = 6 cm, height = 8 cm. slant height, l = 10 cm
volume = (1/3)πr²h = (1/3)π×(6)²×8 = 96π cm³
curved surface area = πrl = π×6×10 = 60π cm²
and when it is revolved around 6 cm
radius = 8 cm, height = 6 cm, slant height , l =10 cm
∴ volume =(1/3)πr²h = (1/3)π×(8)²×6 = 192π cm³
slant height =πrl =π×8×10 = 80π cm²
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