Physics, asked by farooq9, 3 months ago

A rigid bar AB is acted upon by force as shown in the diagram. Reduce the force into :
a. SINGLE FORCE
b. SINGLE FORCE AND COUPLE AT D
c. SINGLE FORCE AND COUPLE AT C​

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Answered by Anonymous
1

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Answered by Talentedgirl1
4

Answer:

(i) A single force: A single force means just to find out the resultant of the system. Since there are parallel force i.e resultant is sum of vertical forces, R = 32.5 –150 + 67.5 –10 = -60 R = (∑V2)1/2 R = 60N Let d = Distance of resultant from A towards right. To find out location of resultant apply varignon’s theorem : R.d = 150 × 1 – 67.5 × 2 + 10 × 3.5 60.d = 150 × 1 – 67.5 × 2 + 10 × 3.5 d = 0.833 m i.e resultant is at a distance of 0.83 m from A. (ii) A single force and a couple at A: It means the whole system is to convert in to a single force and a single couple. Since we convert all forces in to a single force i.e. resultant. Now apply two equal and opposite force i.e. ‘R’ at point A. Now force ‘R’ which is act at point E and upward force which is act at point A makes a couple of magnitude, Magnitude = Force × distance = 60 × 0.833 = 49.98 Nm and a single force of magnitude = 60N (iii) A single force and a couple at B: Since AE = 0.833 m, then BE = 3.5 – 0.833 = 2.67 m Now, the force R = –60N is moved to the point B, by a single force R = –60N and a couple of magnitude = R × BE = –60 × 2.67 = 160 Nm. Hence single force is 60 N and couple is 160 Nm

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farooq9: is it a similiar question
Talentedgirl1: I have answered your this question
farooq9: sorry. this isnt the right answer that i want though
Talentedgirl1: Ok
Talentedgirl1: sorry
farooq9: thanks a lot ♥️
farooq9: i need an answer based on mechanics
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