A rigid body of mass m kg is lifted uniformly by a man to a height of one metre in 30 sec. Another
man lifts the same mass uniformly to the same height in 60 sec. Calculate the ratio of work done on
the body against gravitation by them.
Answers
Answered by
2
Explanation:
Force 1 = mg = m*g
Force 2 = mg = m*g
Work/time = Power
Work is a state Function which does not depend upon path or time.
Work 1 = m1× (g1)× (h1) = mg×(1)
Work 2 = m2 × g2 × h2 = mg×(1)
W1/W2 = mg/mg = 1
Answered by
3
Answer:
the of thier work would be
1:2
because the 1st man lifts it in 30 seconds
and the 2nd in 60 seconds which is actually twice of the first
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