a rigid body rotates about a fixed axis with variable angular speed (in rad /s) w=3-5t at any time t (in second) . the angle through which it rotates before it comes to rest is
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Answer
- Angle of rotation before coming to rest = 0.9 Rad
Explanation
Given:-
- A rigid body rotates about a fixed axis with a variable angular speed (in rad/sec) at any time 't' (in seconds)
- angular speed, ω = 3 - 5t rad/sec
To find:-
- The angle through which it rotates before coming to rest, θ =?
Formula required:-
- The Formula for instantaneous angular velocity
ω = d(θ) / d(t)
[Where ω is angular acceleration, θ is angular displacement, t is the time]
Solution:-
As given,
we need to find the angle of rotation just before the body comes to rest.
so, at that time angular velocity (ω) will be zero.
→ ω = 0
→ 3 - 5t = 0
→ -5t = -3
→ t = 3/5 sec
Now, Using the formula for instantaneous angular acceleration
→ ω = d(θ) / d(t)
→ d(θ) = ω d(t)
[Integrating both sides]
→ ∫ d(θ) = ∫ [ω d(t)]
→ θ = ∫[(3 - 5t) d(t)]
→ θ = 3t - (5t²/2)
[Now, putting t = 3/5]
→ θ = 3×3/5 - [5(3/5)²/2]
→ θ = 9/5 - 9/10
→ θ = 9/10 = 0.9 rad
Therefore,
- The Angle at which body rotates before coming to rest is 0.9 Radians.
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