Question

A ring of diameter 0.4 m and mass 10 kg is rotating about its
through centre and perpendicular to its plane then moment
the ring is
1) 0.4 kgm 2) 0.3 kgm? 3) 0.2 kgm?
4) 0.1 kgm?​

Answer 1

Answer:

It's too simple dear..... First be my girlfriend for your answer.....

Explanation:

Moment of inertia of a ring in above condition is MR^2.....

Your answer is...

(10kg)(0.2m)^2=10/25=0.4kgm.....

Thanks my love....