A ring of diameter 0.4 m and mass 5 kg is revolving with 840 cycles/minute about its geometrical Axis.Find its angular momentum and rotational kinetic energy
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Angular Momentum = I ω
= mr² × ω
= mr² × 2 π f
= 5 kg × (0.4/2 m)² × 2 π × 840/60 Hz
= 17.6 kg m²/s
Rotational Kinetic energy = (Angular Momentum)² / (2 I)
= (Angular Momentum)² / (2 mr²)
= (17.6 kg m² / s)² / (2 × 5 kg × (0.4/2 m)²)
= 774.4 Joule
= mr² × ω
= mr² × 2 π f
= 5 kg × (0.4/2 m)² × 2 π × 840/60 Hz
= 17.6 kg m²/s
Rotational Kinetic energy = (Angular Momentum)² / (2 I)
= (Angular Momentum)² / (2 mr²)
= (17.6 kg m² / s)² / (2 × 5 kg × (0.4/2 m)²)
= 774.4 Joule
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