Question

a ring of diameter 0.4m and mass 10 kg is rotating about its geometrical axis at the rate of 35 rotation per second find moment of inertia, angular momentum,rotational kinetic energy of ring​

Answer 1

The angular momentum of the ring is.

=10×(0.2)2×2×227×20=50.28kg-m2s-2. A ring of diameter 0.4m and of mass 10kg is rotating about its axis at the rate of 2100 rpm.

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Answer 2

Answer:

here's your answer

Explanation:

10×(0.2)2×2×227×20=50.28kg-m2s-2. A ring of diameter 0.4m and of mass 10kg is rotating about its axis at the rate of 2100 rpm.

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