Question

A ring of mass 10kg and diameter 0.4m is rotated about its axis, if it makes 120 revolution per minute, then it's angular momentum will be:​

Answer 1

angular momentum, L = I w

we know I = MR²

I = 10 x 0.2 x 0.2 = 0.4

w = 2πv = 2 x 3.14 x 120/60s = 12.56

L = 0.4 x 12.56 = 5.024 kgm²/s