Physics, asked by nehashetty0305, 1 month ago

A ring of mass M and radius R is rotating with angular velocity w about central axis
Lying flat on a smooth horizontal surface. The tension developed in
the ring is

Answers

Answered by ValeryLegasov
4

Mw²R/2π

Method 1

You can assume a small portion of the rotating ring and evaluate the forces for force angular acceleration equation

Method 2

You can assume a half ring and evaluate the force angular acceleration equation on the centre of mass of the half ring

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Answered by shilpa85475
0

Given a ring with mass 'M' and radius 'R.'

The ring has an angular velocity = ω rad/s

Let the tension in the ring be = T Newton

Let us assume a small portion AB on the ring.

The net force on the section AB is 2Tsin\theta

The net force would be directed towards center C.

2Tsin\theta = 2T\theta (As the angle \theta is small)

The mass of the portion AB is = 2R\theta(M)

For the circular portion,

2T\theta = 2R\theta(M) \omega^{2} \\T= M\omega^{2}R

Thus, the tension appearing in the ring is Mω²R.

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