Question

A ring of mass m and Radius R oscillate about point O as shown in figure, then it's time period is​

Answer 1

Answer:

T=2π√2R/g.

Explanation:

Since, the point of the axis of rotation is present at a periphery of the circle so the moment of inertia of the point O will be I=MR^2 + MR^2=2MR^2. Since, the moment of inertia of a ring is MR^2. Now to get the time period of the ring we know that the time period of a body with moment of inertia I is given by the T=2π√(I/MgR).

Now, substituting the values of the I we will get that T=2π√(2MR^2/MgR). Which on solving we will get that T=2π√2R/g.

Answer 2

Answer:

π√8R/g is the correct answer guys..