Physics, asked by learnerenthusiast, 2 months ago

A ring of mass m slides from rest on the smooth rod as shown in the figure, due to the block of mass m. Pulley and string are massless. Then find the speed of ring when the string become straight. (Given theta = 60°)
(A) 4√gh
(B) √2gh
(C) 2√2gh
(D) 8√gh

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Answered by brgd176
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shown in the figure, due to the block of mass m . Pully and string are massless. Then find the speed of ring when the string become straight. (Given e = 60°) B smooth m (A) 4/gh (B) 2gh (C) 2/2gh (D) 8/gh .

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