Question

A ring of radius 2.0 m and of mass 2 kg is rolling on a horizontal plane.The speed of its centre of mass is 50 cm/s. calculate the moment of inertia and the total kinetic energy of the ring

Answer 1

Moment of inertia I = mr^2
m =2kg; r=2m
I= 2x2^2=8 kgm^2

Kinetic Energy K =1/2 mv^2
V=50cm/s = 0.5m/s
K = 0.5 x 2 x 0.5^2 = 0.25 Joules