Question

a ring of radius R has a charge Q it is cut by the dl. find the electric field at the centre​

Answer 1

Answer:

HOPE IT HELPS ^_^

Answer 2

Answer:

Explanation:

The electric field due to full ring is zero at center when arc of length dl is cut, the electric field becomes non zero, so

E  small arc  =−E  rest of portion

​If λ be the line charge density, Q=λ.2πr⇒λ=Q/  2πr

Charge on cut part is dq=λ.dl=  Qdl /2πr

​The electric field at center due to arc of length dl is E   =1/  4πϵ  *Qdl/2pie r^3

                                                                                           =Qdl /8π^2 ϵ  r^2