A ring of radius R has charge -Q distributed uniformly over it. Calculate the charge (q) that should be placed at the center of the ring such that the electric field becomes zero at a point on the axis of the ring. the value of q is
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answer 2
Explanation:
The electric field due to a ring of radius R at a point on its axis is E=k(z2+R2)3/2−Qz
Electric field at point P(z=R) is E1=k(R2+R2)3/2−QR=−k22R3QR=−k22R2Q
Electric field at P due to center charge q is E2=kR2q
As the net field at P is zero so
E1+E2=0
or −k22R2Q+kR2q=0
⇒q=22Q=4Q2
hope it helps
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