A ring of radius r has given a charge Q and uniformly distributed over its length. If a charge qis placed at the centre. The electric potential energy of the charge q will be
kqQ/r^2
kqQ/r
-kq Q /r
Zero
Answers
Answered by
0
Answer
Correct option is
C
8π
2
ε
0
R
2
T is tension in the ring.
Electrostatic force in radial direction will balance the tension component in that direction
2Tsinθ=
4πε
0
R
2
2πR
qQ(2θR)
angle θ is very small then sinθ=θ
2Tθ=
8π
2
ε
0
R
2
qQ2θ
T=
8π
2
ε
0
R
2
Answered by
1
ur answer is zero
Explanation:
option d
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