Question

A ring of radius R has uniform linear charge density 'X'. The electric field at the centre of ring is​

Answer 1

The electric field:

         The electrical field is that the physical field encircled by electrically charged particles and exerts a force on all differentiy charged particles inside the sector, either attracting or repellent them. It conjointly refers to the physical field of a system of charged particles

Explanation:

The electric field of a hoop is an electrical charge on the axis of the ring that's superposing by the purpose charge fields of small charge components. This ring field is used as part to calculate the electrical field of a charged disc.

The electric field is mathematically expressed as:

E =  $\displaystyle \frac{Q }{2\pi\varepsilon _or^2 }$

where:

           E =  electric field

           Q = electric charge

           $\displaystyle \varepsilon _0$ = electric constant

           r = radius of circle

But electric charge at the center of ring id zero

i.e. Q = 0

∴    E  =  $\displaystyle \frac{ 0}{2\pi\varepsilon _or^2 }$

∴   E   = 0

Hence the electric field at the center of the ring is 0 of radius r.