A ring of radius r is charged uniformly with a charge +q. the elctric field at any point on its axis at a distance r from the circumference of the ring will be
Answers
Answered by
1
think your answer is wrong, because q and 4q are positive and in order for the net force to be zero, forces on q have to cancel each other out, so if 4q is positive, then Q has to be negative so that forces are opposite.
Distance between Q and 4q = x and Distance between 4q and q is x/2.
So distance between Q and q is = x+x/2 = 3x/2
If the force applied by Q on q is F1 and force applied by 4q on q is F2.....
F1= kQq x 2²/ 9x² = 4kQq/9x²
F2= k4qxq x 2²/x² = 4kq²/x²
F1 + F2 = 0
F1 = -F2
4kQq/9x² = -4kq²/x²
Q/9 = -q
Q = -9q
Distance between Q and 4q = x and Distance between 4q and q is x/2.
So distance between Q and q is = x+x/2 = 3x/2
If the force applied by Q on q is F1 and force applied by 4q on q is F2.....
F1= kQq x 2²/ 9x² = 4kQq/9x²
F2= k4qxq x 2²/x² = 4kq²/x²
F1 + F2 = 0
F1 = -F2
4kQq/9x² = -4kq²/x²
Q/9 = -q
Q = -9q
Similar questions