A ring shaped electromagnet has an air gap of 6mm and cross sectional area of 12 cm2. The mean length of the core (excluding air gap) is 60cm. Calculate the mmf required to produce a flux density of 0.4 Wb/m2 in the gap. Take the relative permeability of the material as 400.
Answers
Answer:
G I V E N :
Find the third side of the triangles whose
(a) Two sides : 4 cm, 5 cm; Perimeter = 15 cm
(b) Two sides : 6 cm, 9 cm; Perimeter = 20 cm
(c) Two sides : 5 cm, 2 cm; Perimeter = 12 cm
(d) Two sides : 8 cm, 3 cm; Perimeter = 18 cm
(e) Two sides : 8 cm, 5 cm; Perimeter = 24 cm
(f) Two sides : 9 cm, 13 cm; Perimeter = 37 cm
S O L U T I O N :
As we know that Perimeter of a triangle is
\star \: \underline{ \boxed{ \frak{ \green{{ \sf P}erimeter_{(Triangle)} }= \red{{1}^{st} \: side} + \purple{ {2}^{nd} \: side }+ \pink{ {3}^{rd} \: side} }}}⋆
Perimeter
(Triangle)
=1
st
side+2
nd
side+3
rd
side
Here, in all the six cases we need to find the third side
Case (a)
Two sides : 4 cm, 5 cm; Perimeter = 15 cm
Perimeter = 4 cm + 5 cm + 3rd Side
15 cm = 9 cm + 3rd Side
3rd Side = 15 cm - 9 cm
3rd Side = 6 cm
Case (b)
Two sides : 6 cm, 9 cm; Perimeter = 20 cm
Perimeter = 6 cm + 9 cm + 3rd Side
20 cm = 15 cm + 3rd Side
3rd Side = 20 cm - 15 cm
3rd Side = 5 cm
Case (c)
Two sides : 5 cm, 2 cm; Perimeter = 12 cm
Perimeter = 5 cm + 2 cm + 3rd Side
12 cm = 7 cm + 3rd Side
3rd Side = 12 cm - 7 cm
3rd Side = 5 cm
Case (d)
Two sides : 8 cm, 3 cm; Perimeter = 18 cm
Perimeter = 8 cm + 3 cm + 3rd Side
18 cm = 11 cm + 3rd Side
3rd Side = 18 cm - 11 cm
3rd Side = 7 cm
Case (e)
Two sides : 8 cm, 5 cm; Perimeter = 24 cm
Perimeter = 8 cm + 5 cm + 3rd Side
24 cm = 13 cm + 3rd Side
3rd Side = 24 cm - 13 cm
3rd Side = 11 cm
Case (f)
Two sides : 9 cm, 13 cm; Perimeter = 37 cm
Perimeter = 9 cm + 13 cm + 3rd Side
37 cm = 24 cm + 3rd Side
3rd Side = 37 cm - 22 cm
3rd Side = 15 cm
Answer:
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