Question

A Ripe fruit from a tree to the ground in 1 sec. At what height was the fruit initially?​

Answer 1

mango is ripe fruit from a tree to the ground in in1sec

Answer 2

Answer:

The fruit was at a height of 5 m initially.

Explanation:

Here time is given which is 1 sec and initial velocity of fruit will be zero.  

T = 1 sec and u = 0 (initial velocity)

$\mathrm{S}=\mathrm{ut}-1 / 2 \mathrm{gt}^{2}$

In the above equation negative sign will be used because displacement is directed downward.  

$\mathrm{S}=0 \times 1-1 / 2 \times 10 \times 1^{2}$

S = - 5 meter.

It is a displacement form a point where fruit start to fall and negative value indicates downward displacement.