Math, asked by keeratpunia, 9 months ago

A river is flowing with speed 4 km/hr. A person is having speed 4 km/hr in still
water. Person wants to reach at point B (directly) opposite end of the river. Then
B
4km/hr
A
He should swim making an angle 45° with line AB
Person will never reach at point B
Person has to have speed less than 4 km/hr wrt river to reach at B
Speed of person w.rt. river is 4 v2 km/hr​

Answers

Answered by manjubaladalabehera
0

Answer:

Bro your answer

Step-by-step explanation:

A swimmer swims in still water at a speed =5 km/hr. He enters a 200 m wide river, having river flow speed =4 km/hr at point A and proceeds to swim at an angle of 127

with the river flow direction. Another point B is located directly across A on the other side. The swimmer lands on the other bank at a point C, from which he walks the distance CB with a speed =3 km/hr. The total time in which he reaches from A to B is

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ANSWER

V

S

=V

SR

+V

R

V

S

=(V

R

−V

SR

Sin30

).(0.05)

Displacement along x−axis=

d=(V

R

−V

S

RSin37

).(0.05)

=[4−5(

5

3

)].(0.05)

=0.05km

=50m

journey time (only while swimming)

=

V

VR

cos37

200×10

−3

= 0.05hr

total time =

3km/hr

50×10

−3

km

+0.05hr

=

3

0.05

+0.05=

3

0.20

=0.0666hr=4mins

solution

Answer ByavatarToppr

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