Question

A road 2m wide is constructed all around outside a circular garden of radius 35m.
Find the area of the road. (take π =
22
7

Answer 1

Answer:

width= 2m

outer radius(R) = 35m

inner radius (r) = 35+2= 37

area of road = outer area - inner area

= πR^2 - πr^2

=π(R^2-r^2)

= 22/7(37^2-35^2)

=22/7×144

=452.6 m2

Kindly check whether it is correct

Answer 2

Answer:

Hence, the area of the road is 452.6m².

Step-by-step explanation:

As per the data provided in above given question.

The given data is as follows.

A road is 2m wide and constructed all around outside a circular garden of radius 35m.

We have to find the area of the road.

According to the question,

We have, inner radius of road= 35m.

And outer radius of road 35m+2m=37m.

To find  the area of the road we have to subtract outer area from inner area.

As we know that area of a circle is πr²,as the road is in circular.

We have π=$\frac{22}{7}$

Area of the road=Outer area - Inner area

 $=\frac{22}{7}(37)^{2} -\frac{22}{7}(35)^{2}$

$Taking \frac{22}{7} common$

 $=\frac{22}{7} [(37)^{2}-(35)^{2}]$

 [tex]=\frac{22}{7}\times144\\ =\frac{3168}{7} \\ =452.6m^{2} [/tex]

Hence, the area of the road is 452.6m².