Question

A road 7/4 km. long was prepared in 4 days. On the first day 2/5of the road, on 2nd day 1/7 of the road and on the 3rd day 5/21 of the road was repaired. What length of the road was repaired on the 4th day ?​

Answer 1

Answer:

23/60

Step-by-step explanation:

Take the LCM of 5, 7, and 21

i.e. 105

Hence the fractions for the work done will be

42/105 + 15/105 + 25/105 = 82/105

Total work done till now will be 82/105

Remaining work is 105 - 82 = 23/105

Therefore, The length of road being repaired on the last day is

23/105 * 7/4 = 23/60.

Hope it helped you ..............