Question

A road from A to B which is 11.5 km long first goes uphill then crosses a plane and then goes Downhill a person starts walking A to B takes 2hr 54min to cover the route from A to B and it takes 3hr 6min while his return his speed on the uphill 3km/h on the plane is 4km/h and Downhill is 5km/h what is the distance of the plane part of the journey

Answer 1

Answer:4^{-2} = (\frac{1}{4})^{2}

4^{-2} = (\frac{1}{4})^{2}4^{-2} = (\frac{1}{4})^{2}

Explanation:4^{-2} = (\frac{1}{4})^{2}4^{-2} = (\frac{1}{4})^{2}