Question

A road is 4 km 800 m long. If trees are planned on both its sidesat intervals of 9.6 m, hoe many trees were planned

Answer 1

Answer:

The answer is 1002 that the trees were planned

Answer 2

To Find:-

• How many trees were planted?

Given:-

• Length of the road = 4km 800m
• Distance between two plants 9.6m

Solution:-

Total length of the road = 4km 800m (1km=1000m)

= 4000 + 800

= 4800m

Given distance between two plants = 9.6m

step-by-step explanation:

Number of trees planted on each side

= Length of the road ÷ Distance between two plants + 1

⟹ ( 4800m ÷ 9.6m ) + 1

$\implies \bigg(\dfrac{4800}{1} \div \dfrac{96}{10}\bigg) + 1$

$\implies \bigg(\dfrac{4800}{1} \times \dfrac{10}{96}\bigg) + 1$

⟹ 50 × 10 + 1

⟹ 500 + 1

⟹ 501

So,

Total number of trees planted on both sides of the road

= Number of trees planted on side of the road ×2

= 501 × 2

= 1002

$\underline\bold{Required \: Answer}$

Number of tress planted = 1002