Question

A road network covers some cities. City c can be reached only from the city a or city

b. The distance from a to c is 65 km and that from b to c is 30 km. The shortest distance from a to b is 58 km. The shortest distance from city p to a is 420 km and the shortest distance from city p to b is 345 km. The shortest distance from city p to city c in kms is:

Answer 1

The shortest distance from city P to C is 375 kms.

Step-by-step explanation:

As we can see there are only 4 routes from city P to C

a) from P to A and then A to C

So , distance in this route will be

= 420 + 65

= 485 kms

b) From P to B and then B to C

So , distance in this route will be

= 345 + 30

= 375 kms

c) from P to A then A to B and then B to C

So , distance in this route will be

= 420 + 58 + 30

= 508 kms

d) From P to B then B to A and then A to C

So , distance in this route will be

= 345 + 58 + 65

= 468 kms

Hence we can see that the shortest distance from P to C is 375 kms via route b) i.e from P to B and then B to C.

Hope it helps you...