A road network covers some cities. City C can be reached only from the city A or city B. The distance from A to C is 65 kms and that from B to C is 30 kms. The shortest distance from A to B is 58 kms. The shortest distance from city P to A is 420 kms and the shortest distance from city P to B is 345 kms. The shortest distance from city P to city C in kms is:
Answers
Answer:
The shortest distance from city P to C is 375 kms.
Step-by-step explanation:
As we can see there are only 4 routes from city P to C
a) from P to A and then A to C
So , distance in this route will be
= 420 + 65
= 485 kms
b) From P to B and then B to C
So , distance in this route will be
= 345 + 30
= 375 kms
c) from P to A then A to B and then B to C
So , distance in this route will be
= 420 + 58 + 30
= 508 kms
d) From P to B then B to A and then A to C
So , distance in this route will be
= 345 + 58 + 65
= 468 kms
Hence we can see that the shortest distance from P to C is 375 kms via route b) i.e from P to B and then B to C.
Answer:
375 km
Step-by-step explanation:
See Attached.
From the diagram, we can see that the shortest path is:
Route = P to B to C
Distance = 345 + 30 = 375 km
Answer: 375 km
