A road of width 3.5 M is to be built around a circular garden of radius 14 M find the area of the road also find the cost of fencing the garden of the rate of fencing is rupees 70 per meter.
Answers
Answer:
Given,
width of road = 3.5 m
radius of garden (without road) = 14m
radius of a garden (including road) = (14 + 3.5)m
= 17.5 m
Therefore,
Area of garden (including road) = π r^2
= 22/7 × 17.5^2 sq. m
= 22/7 × 17.5 × 17.5 sq. m
= 22 × 2.5 × 17.5 sq. m
= 55 × 17.5 sq. m
= 962.5 sq. m
Therefore,
Area of garden (without road) = π r^2
= 22/7 × 14^2 sq. m
= 22/7 × 14× 14 sq. m
= 22 × 2 × 14 sq. m
= 44 × 14 sq. m
= 616 sq. m
Answer :- Area of the road = ( 962.5 - 616) sq. m
= 346.5sq. m
Therefore,
Circumference of the garden = 2 π r
= 2 × 22/7 × 14 m
= 2 × 22 × 2 m
= 88 m
If the cost of fencing 1 m garden is ₹ 70
Then, the cost of fencing 88 m garden is = ₹ (70 × 88)
= ₹ 6160
Answer :- The cost of fencing the garden is ₹ 6160