A road rolled is 140 cm long . its diameter is 84 cm . it takes 1000 complete revolutions once over to level the road. find the cost of levelling the road at rupees 50 per 100 square metres
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Therefore the cost of leveling the road is rupees 123200
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area covered in one complete revolution =surface area of road =2pi.r.h
=2 x 22/7 x 42 x 140 cm^2
=12 x 22 x 140 cm^2
=36960 cm^2
covered area in 1000 revolution =1000 x surface area of road roller =36960 x 10^3 cm^3
=3696 m^2
now,
cost = surface area of roller x rate
=3696 x 50/100 =1848 Rs
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