Question

A road roller has a diameter 0.7 m and its width is 1.2 m. Find the least number
of revolutions that the roller must take in order to level a playground of size
120 m x 44 m.
PLEASE ANSWER FAST
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Answer 1

Answer:

Given diameter of the road roller, d = 0.7 m

Radius, r = d/2 = 0.7/2 = 0.35 m

Width, h = 1.2 m

Curved surface area of the road roller = 2rh

=2 ×(22/7)×0.35×1.2

= 2.64 m2

Area of the play ground = l×b

= 120×44

= 5280 m2

Number of revolutions = Area of play ground / Curved surface area

= 5280/2.64

= 2000