Question

A road roller has a diameter 2 m and length 4 m. find the area of the road levelled by it is 700 revolutions

Answer 1

Step-by-step explanation:

d=2m

r=1m

h=4m

CSA= 2$\pi$rh

=2 x $\frac{22}{7}$ x 1 x 4

= $\frac{176}{7}$cm²

Area for 700 revolutions

= $\frac{176}{7}$ x 700

176 x 100

17600cm²

Hope this helps

:)

Answer 2

Step-by-step explanation:

d=2m

r=1m

h=4m

CSA= 2\piπ rh

=2 x \frac{22}{7}

7

22

x 1 x 4

= \frac{176}{7}

7

176

cm²

Area for 700 revolutions

= \frac{176}{7}

7

176

x 700

176 x 100

17600cm²