A road roller has a radius of 42 cm and length 3m. How much areais required to cover the outer surface of 5 such road rollers?
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Solution:
Given Diameter of roller =84 then radius
=84/2=42 or 0.42 m and height =1m In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = pi*r * h =2^ * 22/7^ * 0.42^ * 1
Area of the road in one revolution =2.64
sq m
Therefore, in 750 revolutions, the area of
=1980 sq m
the road =2.64^ * 75c
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