Question

A road roller has length 2m and radius 140cm. find the number of revolutions required by the roller to cover an area of 616 aq m

Answer 1

❄❄HEY MATE!!! HERE IS YOUR ANSWER❄❄

➡Radius of Road Roller in m =

$\frac{140}{100} = 1.4m$

➡Length of Road Roller, h = 2m

➡Area Covered in the 1 Revolution of The Road Roller = Curved Surface Area Of Orad Roller.

➡Curved Surface Area of Road Roller = 2πrh

$2 \times \frac{22}{7} \times 1.4 \times 2$

➡
$17.6m ^{2}$

➡Therefore, Number of Revolutions Required by the Road Roller to cover an area of 616 cm² =
$\frac{616}{17.6} = 35$

➡Therefore, Number of Revolutions Required by the Road Roller to cover an area of 616 cm² is 35.

❄❄HOPE THIS HELPS❄❄

Answer 2

Answer:

35 Is the ans

Hope This Helps You Bro <3