Question

A road roller is 140cm. long it's diameter is 84cm it takes 1000 complete revolution once over to level the road . find the cost of levelling the road at rs. 50.per 100 square metres with solutions

Answer 1

Area covered in complete revolution = surface area of road = 2$\pi rh$
= 2*22/7*42*140
=36960 cm²
covered area in 1000 revolution= 1000*surface area of road roller 36960*1000 = 3696m ²
Cost of levelling the road = 3696*.50 
= Rs. 1848






Hope it helps... :)

Answer 2

Answer:

I love it when it was the first time in my life and the other side of the question in an examination of the same numbers and websites for a few weeks and allowed me to do it