Question

a road roller is 140cm . long its diameter is 84 cm. it takes 1000 complete revolutions once over to level the road .find the cost of levelling the road at Rs.50 per square meters.​

Answer 1

Answer:

Explanation:

Length of road roller, l = 140 cm

Diameter = 84 cm

Hence,

radius, r = 42 cm

Area covered in 1000 revolutions = 1000 × curved surface area of roller

= 1000 × 2πrl = 1000× 2 × π × 42 × 140 = 11760000π

Given that the cost for leveling road is 50 rs per squ meter.

Total cost = total area covered(in m) × 50 = 1176 × 50 = 58800 Rupees

Hope that was clear.