Math, asked by shloka5405, 6 months ago

? A road roller is 2 m long and has a radius of 42 cm. It costs Rs 0.20 for every
m2 of road levelled. If the total cost was Rs. 1584, then how many revolutions
did the road roller make?

Answers

Answered by amitsnh
4

Answer:

1500 revolutions

Step-by-step explanation:

radius of roller = 42 cm = 0.42 m

area covered by roller in one revolution

= 2πrh (since roller is a cylinder)

= 2*(22/7)*0.42*2

= 5.28 m2

cost of rolling per m2 = 0.20 rupee

total cost of rolling = rupee 1584

area rolled = 1584/0.2

= 7920 m2

no. of revolution required to cover this area

= 7920/5.28

= 1500 revolutions

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