a road roller is 210 m long. its diameter is 63 cm. if it takes 480 complete revolutions to levle the road once, then find the cost of levelling the road at RS.50 per 100 m
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h=210m
d=63cm= 0.63m
r=0.63/2m
Lateral surface area of cylinder=2|| r h
(2x22x0.63x210)/7x2=4158m^2
Cost for 100m^2 area. =₹50
Total cost for levelling the road=4158x50/100=₹ 2079
d=63cm= 0.63m
r=0.63/2m
Lateral surface area of cylinder=2|| r h
(2x22x0.63x210)/7x2=4158m^2
Cost for 100m^2 area. =₹50
Total cost for levelling the road=4158x50/100=₹ 2079
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