A road roller is cylindrical in shape. Its circular ends has diameter 1.4m and its width is 4m. It is used to level a playground measuring 70m x 44m. Find the minimum number of complete revolutions that the roller must make in order to cover the entire ground once.
Answers
Answered by
3
given:-
diameter of roller = 250 cm = 2.5m
width of roller = 1.4m
radius of the roller = 1.25m
we know that
curved surface area = 2×22/7×1.25×1.40
= 44 × 1.25 × 0.20
=11m^2
area of ground = length × breath
= 25 × 10
= 250 m^2
number of revolutions to cover the field= Area of field/ CSA of roller.
= 250/11
= 22.727 revolutions approx
Answered by
1
this is the answer for your question
Attachments:
Similar questions