Question

A road roller is,in the shape of cylinder having diameter 96cm and lenght 110cm The road roller takes,1200 complete revolution to level an entire road.If tge width of the road is 9.6mFind the lenght of the road​

Answer 1

Answer:

414.5 m

Step-by-step explanation:

A road roller is,in the shape of cylinder having diameter 96cm and lenght 110cm The road roller takes,1200 complete revolution to level an entire road.If tge width of the road is 9.6mFind the lenght of the road​

Area covered in 1 revolution = Surface Area of roller

Surface area of Roller = 2 π R h

π = 3.14  R = Diameter/2 = 96/2 = 48 cm = 0.48 m

h = Length = 110 cm = 1.1 m

Surface area of Roller = 2 * 3.14 * 0.48 * 1.1 = 3.316 m²

Area covered in 1200 revolution = 1200 * 3.316 = 3979.2 m²

Let say Length Of Road = L m

Width of road = 9.6 m

Area of Road = 9.6L m²

9.6L = 3979.2

=> L = 3979.2/9.6

=> L = 414.5 m

Answer 2

length of road = 4.1485 km

diameter of cylinderical roller , d = 96cm = 9.6m

so, radius of cylindrical roller, r = 4.8m

length of cylindrical roller, l = 110cm or 1.1m

roller takes 1200 complete revolutions to level an entire road.

curve surface area of cylinderical roller = 2πrl = 2 × 22/7 × 4.8 × 1.1 m²

here, area of road = 1200 × curve surface area of cylinderical roller

width × length = 1200 × 2 × 22/7 × 4.8 × 1.1

or, 9.6 × length = 1200 × 22/7 × 9.6 × 1.1

or, length = 1200 × 22/7 × 1.1 = 4,148.5m

hence, length of road = 4.1485 km