A road roller is150 cm long has a diameter of 70 cm. To level a playground it takes 750 complete revolutions. Determine the cost of levelling the playground at the rate of 25 rupees per m2
i ma in exam send ans fast pls
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Step-by-step explanation:
Area of playground = 750 × CSA of roller
= 750 × 2 × 22÷7 × 35 × 150
= 750 × 33000
= 24750000 cm^2
= 2475 m^2
Cost of leveling = 2475 × 0.75
= Rs 1856.25
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