Math, asked by purinipavan, 3 months ago

A road roller is150 cm long has a diameter of 70 cm. To level a playground it takes 750 complete revolutions. Determine the cost of levelling the playground at the rate of 25 rupees per m2

i ma in exam send ans fast pls

Answers

Answered by RomanEmpire2006
2

Step-by-step explanation:

Area of playground = 750 × CSA of roller

= 750 × 2 × 22÷7 × 35 × 150

= 750 × 33000

= 24750000 cm^2

= 2475 m^2

Cost of leveling = 2475 × 0.75

= Rs 1856.25

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