Question

A road roller makes 250complete revolution to move

once over to level a road. Find the area of the road

levelled if the diameter of the road roller is84cm

and length is 1m​

Answer 1

660m² is your answer for this question.

Answer 2

Step-by-step explanation:

no. of revolution= 250

length = height = 1m= 100cm

radius = 84/2= 42

area of road = 250x LSA of roadroller (cylinder)= 2 x pie x r x h

which gives

$= 2 \times \: \pi \: r \: h \\ 2 \times \frac{22}{7} \times 42 \times 100 = 26400cm {}^{2}$

therefore area of road = 250x 26400

= 66000 cm2