a road roller takes 100complete revolution to move once over to level a road find the area of the road if the diameter of the road roller is 140cm and lenght is 2m
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Answered by
36
Q) A road roller takes 100 complete revolution to move once over to level a road find the area of the road if the diameter of the road roller is 140 cm and length is 2 m .
☆ Given :
- Roller takes 100 revolutions .
- Diameter (of roller) = 140 cm = 1.4 m
- Length (of roller) = 2 m
☆ To Find :
- Area of the road = ?
☆ Solution :
- Roller is cylindrical .
- The CSA of the roller is used to level .
- Radius = 1.4m/2
So , The area of road would be 880 m² .
_________________________
☆ Know more about Cylinder :
• Volume of Cylinder = πr²h
• TSA of Cylinder = 2πr(h+r)
• CSA of Cylinder = 2πrh
• Area of base/top = πr²
→ The unit of volume = unit³
→ The unit of surface area = unit²
Answered by
36
Given :
- Diameter of the road roller = 140 cm = 1.4 m
- Radius of the road roller = 1.4/2 = 0.7 m
- Length of road roller = 2 m
- Total revolution of the road roller = 100
To find :
- Area of the road ?
Solution :
★ According to the Question:
- 1 revolution of the road roller = Curved surface area of roller
➣ 100 revolution = 100 × CSA = Area of road
Therefore,
➻ Area of road = 100 × 2 × 22/7 × 0.7 × 2
➻ Area of road = 100 × 2 × 22 × 0.1 × 2
➻ Area of road = 100 × 88 × 1/10
➻ Area of road = 10 × 88
➻ Area of road = 880 m²
∴ Hence, Area of road is 880 m².
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★ Formulas related to it :
- Area of base of cylinder = πr²
- Curved surface area of cylinder = 2πrh
- Total surface area of cylinder = 2πr(r + h)
- Volume of cylinder = πr²h
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